Optimal. Leaf size=100 \[ -\frac{2 \cos ^5(c+d x)}{15 a^2 d}-\frac{\sin (c+d x) \cos ^3(c+d x)}{6 a^2 d}-\frac{\sin (c+d x) \cos (c+d x)}{4 a^2 d}-\frac{x}{4 a^2}-\frac{\cos ^7(c+d x)}{3 d (a \sin (c+d x)+a)^2} \]
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Rubi [A] time = 0.126212, antiderivative size = 100, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.148, Rules used = {2859, 2682, 2635, 8} \[ -\frac{2 \cos ^5(c+d x)}{15 a^2 d}-\frac{\sin (c+d x) \cos ^3(c+d x)}{6 a^2 d}-\frac{\sin (c+d x) \cos (c+d x)}{4 a^2 d}-\frac{x}{4 a^2}-\frac{\cos ^7(c+d x)}{3 d (a \sin (c+d x)+a)^2} \]
Antiderivative was successfully verified.
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Rule 2859
Rule 2682
Rule 2635
Rule 8
Rubi steps
\begin{align*} \int \frac{\cos ^6(c+d x) \sin (c+d x)}{(a+a \sin (c+d x))^2} \, dx &=-\frac{\cos ^7(c+d x)}{3 d (a+a \sin (c+d x))^2}-\frac{2 \int \frac{\cos ^6(c+d x)}{a+a \sin (c+d x)} \, dx}{3 a}\\ &=-\frac{2 \cos ^5(c+d x)}{15 a^2 d}-\frac{\cos ^7(c+d x)}{3 d (a+a \sin (c+d x))^2}-\frac{2 \int \cos ^4(c+d x) \, dx}{3 a^2}\\ &=-\frac{2 \cos ^5(c+d x)}{15 a^2 d}-\frac{\cos ^3(c+d x) \sin (c+d x)}{6 a^2 d}-\frac{\cos ^7(c+d x)}{3 d (a+a \sin (c+d x))^2}-\frac{\int \cos ^2(c+d x) \, dx}{2 a^2}\\ &=-\frac{2 \cos ^5(c+d x)}{15 a^2 d}-\frac{\cos (c+d x) \sin (c+d x)}{4 a^2 d}-\frac{\cos ^3(c+d x) \sin (c+d x)}{6 a^2 d}-\frac{\cos ^7(c+d x)}{3 d (a+a \sin (c+d x))^2}-\frac{\int 1 \, dx}{4 a^2}\\ &=-\frac{x}{4 a^2}-\frac{2 \cos ^5(c+d x)}{15 a^2 d}-\frac{\cos (c+d x) \sin (c+d x)}{4 a^2 d}-\frac{\cos ^3(c+d x) \sin (c+d x)}{6 a^2 d}-\frac{\cos ^7(c+d x)}{3 d (a+a \sin (c+d x))^2}\\ \end{align*}
Mathematica [B] time = 1.24465, size = 262, normalized size = 2.62 \[ \frac{-120 d x \sin \left (\frac{c}{2}\right )+90 \sin \left (\frac{c}{2}+d x\right )-90 \sin \left (\frac{3 c}{2}+d x\right )+25 \sin \left (\frac{5 c}{2}+3 d x\right )-25 \sin \left (\frac{7 c}{2}+3 d x\right )+15 \sin \left (\frac{7 c}{2}+4 d x\right )+15 \sin \left (\frac{9 c}{2}+4 d x\right )-3 \sin \left (\frac{9 c}{2}+5 d x\right )+3 \sin \left (\frac{11 c}{2}+5 d x\right )-5 \cos \left (\frac{c}{2}\right ) (24 d x+5)-90 \cos \left (\frac{c}{2}+d x\right )-90 \cos \left (\frac{3 c}{2}+d x\right )-25 \cos \left (\frac{5 c}{2}+3 d x\right )-25 \cos \left (\frac{7 c}{2}+3 d x\right )+15 \cos \left (\frac{7 c}{2}+4 d x\right )-15 \cos \left (\frac{9 c}{2}+4 d x\right )+3 \cos \left (\frac{9 c}{2}+5 d x\right )+3 \cos \left (\frac{11 c}{2}+5 d x\right )+25 \sin \left (\frac{c}{2}\right )}{480 a^2 d \left (\sin \left (\frac{c}{2}\right )+\cos \left (\frac{c}{2}\right )\right )} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.076, size = 313, normalized size = 3.1 \begin{align*} -{\frac{1}{2\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{9} \left ( 1+ \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2} \right ) ^{-5}}-2\,{\frac{ \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) ^{8}}{d{a}^{2} \left ( 1+ \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) ^{2} \right ) ^{5}}}+3\,{\frac{ \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) ^{7}}{d{a}^{2} \left ( 1+ \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) ^{2} \right ) ^{5}}}-8\,{\frac{ \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) ^{6}}{d{a}^{2} \left ( 1+ \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) ^{2} \right ) ^{5}}}-{\frac{4}{3\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{4} \left ( 1+ \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2} \right ) ^{-5}}-3\,{\frac{ \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) ^{3}}{d{a}^{2} \left ( 1+ \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) ^{2} \right ) ^{5}}}-{\frac{8}{3\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2} \left ( 1+ \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2} \right ) ^{-5}}+{\frac{1}{2\,d{a}^{2}}\tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \left ( 1+ \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2} \right ) ^{-5}}-{\frac{14}{15\,d{a}^{2}} \left ( 1+ \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2} \right ) ^{-5}}-{\frac{1}{2\,d{a}^{2}}\arctan \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.54305, size = 419, normalized size = 4.19 \begin{align*} \frac{\frac{\frac{15 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac{80 \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} - \frac{90 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} - \frac{40 \, \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} - \frac{240 \, \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} + \frac{90 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}} - \frac{60 \, \sin \left (d x + c\right )^{8}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{8}} - \frac{15 \, \sin \left (d x + c\right )^{9}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{9}} - 28}{a^{2} + \frac{5 \, a^{2} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac{10 \, a^{2} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + \frac{10 \, a^{2} \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} + \frac{5 \, a^{2} \sin \left (d x + c\right )^{8}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{8}} + \frac{a^{2} \sin \left (d x + c\right )^{10}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{10}}} - \frac{15 \, \arctan \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{2}}}{30 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.07912, size = 155, normalized size = 1.55 \begin{align*} \frac{12 \, \cos \left (d x + c\right )^{5} - 40 \, \cos \left (d x + c\right )^{3} - 15 \, d x + 15 \,{\left (2 \, \cos \left (d x + c\right )^{3} - \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{60 \, a^{2} d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 131.729, size = 1834, normalized size = 18.34 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.42032, size = 189, normalized size = 1.89 \begin{align*} -\frac{\frac{15 \,{\left (d x + c\right )}}{a^{2}} + \frac{2 \,{\left (15 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{9} + 60 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{8} - 90 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 240 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{6} + 40 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} + 90 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 80 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 15 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 28\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{5} a^{2}}}{60 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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